假如有一个表 test
id name value
1 a pp
2 a pp
3 b iii
4 b pp
5 b pp
6 c pp
7 c pp
8 c iii
id是主键
要求得到这样的结果
id name value
1 a pp
3 b iii
4 b pp
6 c pp
8 c iii
方法1
delete test
where [id] not in (
select max([id]) from test
group by (name + value))
方法2
delete a
from testa left join(
select (id) from test group by name,value
)b on a.id=b.id
where b.id is null