XiaoZhengYu

MySQL层级数据查询

address表结构如下:

address表有如下数据:

现在创建一个函数,获取地址全称:

CREATE DEFINER=`root`@`localhost` FUNCTION `getFullName`(`id` varchar(1000)) RETURNS varchar(1000) CHARSET utf8mb4
    READS SQL DATA
BEGIN

	DECLARE fullName VARCHAR(1000);
	DECLARE parentId VARCHAR(1000);
	DECLARE parentName VARCHAR(1000);
	
	set fullName = (SELECT address.`name` FROM address WHERE address.id = id);
	set parentId = (SELECT address.parentId FROM address WHERE address.id = id);
	
	WHILE parentId IS NOT NULL DO
	    set parentName = (SELECT address.`name` FROM address WHERE address.id = parentId);
			set fullName = CONCAT(parentName,"/",fullName);
	    set parentId = (SELECT address.parentId FROM address WHERE address.id = parentId);
    END WHILE;
	
	RETURN fullName;
END

函数测试:

SELECT
	`address`.`id` AS `id`,
	`address`.`name` AS `name`,
	`getFullName` ( `address`.`id` ) AS `fullName` 
FROM
	`address`

分类:

技术点:

相关文章:

  • 2021-09-15
  • 2021-11-06
  • 2021-12-01
  • 2021-11-16
  • 2021-07-03
  • 2021-10-15
  • 2021-10-11
猜你喜欢
  • 2021-11-13
  • 2021-08-26
  • 2022-02-08
  • 2022-02-08
  • 2021-12-23
  • 2021-05-26
相关资源
相似解决方案