fangpengchengbupter

RecentMutations表的结构如图,现在的需求是需要查找到2017年09月08日前10天的变体总数:

SQL语句:SELECT SUM(MutantNumber) FROM RecentMutations WHERE DATE_SUB( CURDATE() , INTERVAL 10 DAY) <=  RecentMutations.`Date`;

执行的结果为:

 MySQL关于根据日期查询数据

1.查询某日往前10天的数据:

SELECT * FROM RecentMutations WHERE DATE_SUB( CURDATE() , INTERVAL 10 DAY) <=  RecentMutations.`Date`;

2.查询某段日期之间的数据:

SELECT * FROM RecentMutations WHERE  RecentMutations.`Date` BETWEEN \'2017-09-05\' AND \'2017-09-09\';

3.查询某日往前三个月的数据:

SELECT * FROM RecentMutations WHERE  DATE_SUB( CURDATE() , INTERVAL 3 MONTH) <= RecentMutations.`Date`;

4.查询从现在起往前三个月的数据:

SELECT * FROM RecentMutations WHERE  RecentMutations.`Date` BETWEEN DATE_SUB( CURDATE() , INTERVAL 3 MONTH) AND NOW();

5.查询本月的数据:

SELECT * FROM RecentMutations WHERE DATE_FORMAT( RecentMutations.`Date` , \'%Y-%M\') = DATE_FORMAT( NOW() , \'%Y-%M\');

6.查询本周的数据:

SELECT * FROM RecentMutations WHERE YEARWEEK( RecentMutations.`Date`) = YEARWEEK( NOW() );

7.查询上周的数据:

SELECT * FROM RecentMutations WHERE YEARWEEK( RecentMutations.`Date`) = YEARWEEK( NOW() ) - 1;

分类:

技术点:

相关文章:

  • 2021-11-12
  • 2021-12-22
  • 2022-12-23
  • 2021-12-22
  • 2021-12-13
猜你喜欢
  • 2021-11-12
  • 2021-12-28
  • 2022-12-23
  • 2022-03-05
  • 2022-12-23
  • 2021-12-22
相关资源
相似解决方案