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  • 使用 YEAR(), MONTH(), DAY() 来获取年月日

SELECT YEAR(application_date) as years, count(1) FROM patent GROUP BY YEAR(application_date) ORDER BY years

-- YEAR(application_date)   获取年份
-- MONTH(application_date) 获取月份
-- DAY(application_date)    获取日

  • 使用 date_format(application_date\'%Y\'),可自定义日期格式
SELECT date_format(application_date, "%Y") as year, count(1) FROM patent GROUP BY date_format(application_date, "%Y") 

 

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