django上传下载大文件
2014-10-30 21:50 cmsd 阅读(793) 评论(0) 编辑 收藏 举报上传
def upFile(file): upload_dir = \'/tmp/upload/%s\' % username if request.method == \'POST\': upload_file = request.FILES.get(\'file\', None) if upload_file: if not os.path.exists(upload_dir): os.makedirs(upload_dir) filename = \'%s/%s\' % (upload_dir, upload_file.name) f = open(filename, \'wb\') for chunk in upload_file.chunks(): f.write(chunk) f.close()
下载
import os, tempfile, zipfile from django.http import HttpResponse from django.core.servers.basehttp import FileWrapper def send_file(request): """ Send a file through Django without loading the whole file into memory at once. The FileWrapper will turn the file object into an iterator for chunks of 8KB. """ filename = __file__ # Select your file here. wrapper = FileWrapper(file(filename)) response = HttpResponse(wrapper, content_type=\'text/plain\') response[\'Content-Length\'] = os.path.getsize(filename) return response def send_zipfile(request): """ Create a ZIP file on disk and transmit it in chunks of 8KB, without loading the whole file into memory. A similar approach can be used for large dynamic PDF files. """ temp = tempfile.TemporaryFile() archive = zipfile.ZipFile(temp, \'w\', zipfile.ZIP_DEFLATED) for index in range(10): filename = __file__ # Select your files here. archive.write(filename, \'file%d.txt\' % index) archive.close() wrapper = FileWrapper(temp) response = HttpResponse(wrapper, content_type=\'application/zip\') response[\'Content-Disposition\'] = \'attachment; filename=test.zip\' response[\'Content-Length\'] = temp.tell() temp.seek(0) return response