主要是练习while 循环和 if 条件判断的使用
#!_*_coding:utf-8_*_ # Author: hkey def options(list): for i, v in enumerate(list): print(i + 1, v) choice = input(\'\33[34;1m请选择:\33[0m\') return choice def city(list): while True: choice = options(list) if choice == str(len(list)): break def start(): while True: print(\'\33[32;1m欢迎查询省份城市\33[0m\'.center(30, \'#\')) choice = options(prov_list) if choice == \'1\': city(sx) elif choice == \'2\': city(shanxi) elif choice == \'3\': city(sh) if choice == \'4\': break if __name__ == \'__main__\': prov_list = [\'陕西省\', \'山西省\', \'上海市\', \'退出\'] sx = [\'西安市\', \'安康市\', \'咸阳市\', \'返回\'] shanxi = [\'太原市\', \'运城市\', \'返回\'] sh = [\'上海市\', \'返回\'] start()
另一个版本:
# -*- coding: utf-8 -*- prov_list = [\'陕西省\', \'浙江省\', \'退出\'] sx_city_list = [\'西安市\', \'咸阳市\', \'宝鸡市\', \'返回\'] zj_city_list = [\'杭州市\', \'宁波市\', \'绍兴市\', \'返回\'] while True: for k, v in enumerate(prov_list): print(k+1, v) choice = input(\'\33[34;1m请选择:\33[1m\') if choice == \'1\': while True: for k, v in enumerate(sx_city_list): print(k+1, v) choice = input(\'\33[34;1m请选择:\33[1m\') if choice == str(len(sx_city_list)): break elif choice == \'2\': while True: for k, v in enumerate(zj_city_list): print(k+1, v) choice = input(\'\33[34;1m请选择:\33[1m\') if choice == str(len(zj_city_list)): break elif choice == \'3\': break else: print(\'输入序号不存在,请重新输入!\')