hukey

主要是练习while 循环和 if 条件判断的使用

#!_*_coding:utf-8_*_
# Author: hkey

def options(list):
    for i, v in enumerate(list):
        print(i + 1, v)
    choice = input(\'\33[34;1m请选择:\33[0m\')
    return choice

def city(list):
    while True:
        choice = options(list)
        if choice == str(len(list)):
            break

def start():
    while True:
        print(\'\33[32;1m欢迎查询省份城市\33[0m\'.center(30, \'#\'))
        choice = options(prov_list)
        if choice == \'1\':
            city(sx)
        elif choice == \'2\':
            city(shanxi)
        elif choice == \'3\':
            city(sh)
        if choice == \'4\':
            break

if __name__ == \'__main__\':
    prov_list = [\'陕西省\', \'山西省\', \'上海市\', \'退出\']
    sx = [\'西安市\', \'安康市\', \'咸阳市\', \'返回\']
    shanxi = [\'太原市\', \'运城市\', \'返回\']
    sh = [\'上海市\', \'返回\']
    start()
View Code

 另一个版本:

# -*- coding: utf-8 -*-
prov_list = [\'陕西省\', \'浙江省\', \'退出\']
sx_city_list = [\'西安市\', \'咸阳市\', \'宝鸡市\', \'返回\']
zj_city_list = [\'杭州市\', \'宁波市\', \'绍兴市\', \'返回\']

while True:
    for k, v in enumerate(prov_list):
        print(k+1, v)
    choice = input(\'\33[34;1m请选择:\33[1m\')
    if choice == \'1\':
        while True:
            for k, v in enumerate(sx_city_list):
                print(k+1, v)
            choice = input(\'\33[34;1m请选择:\33[1m\')
            if choice == str(len(sx_city_list)):
                break
    elif choice == \'2\':
        while True:
            for k, v in enumerate(zj_city_list):
                print(k+1, v)
            choice = input(\'\33[34;1m请选择:\33[1m\')
            if choice == str(len(zj_city_list)):
                break
    elif choice == \'3\':
        break
    else:
        print(\'输入序号不存在,请重新输入!\')

 

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