-- 某一天所在周的第一天: -- 我们知道国外的星期的第一天是从星期天开始的,所以DAYOFWEEK(\'2017-3-10\')函数的第一天是星期天: SELECT CASE WHEN DAYNAME(DATE(\'2017-3-10\'))=\'Sunday\' THEN DATE_SUB(DATE(\'2017-3-10\'),INTERVAL 6 DAY) ELSE DATE_ADD(\'2017-3-10\',INTERVAL -DAYOFWEEK(DATE(\'2017-3-10\'))+2 DAY) END -- 某一天所在周的最后一天: SELECT CASE WHEN DAYNAME(DATE(\'2017-3-11\'))=\'Sunday\' THEN DATE(\'2017-3-11\') ELSE DATE_ADD(\'2017-3-11\',INTERVAL 7-DAYOFWEEK(\'2017-3-11\')+1 DAY) END -- 某一天的所在月的第一天: SELECT DATE_ADD( DATE_ADD(LAST_DAY(\'2017-03-03\'),INTERVAL 1 DAY ),INTERVAL -1 MONTH ); -- 或 SELECT DATE_SUB(DATE_ADD(LAST_DAY(\'2017-03-03\'),INTERVAL 1 DAY),INTERVAL 1 MONTH) -- 或 SELECT DATE_SUB(LAST_DAY(\'2017-03-03\'),INTERVAL TIMESTAMPDIFF(DAY,\'2017-03-03\',(DATE_ADD(\'2017-03-03\',INTERVAL 1 MONTH)))-1 DAY) -- 某一天所在月的最后一天: SELECT LAST_DAY(\'2017-03-03\'); select DATE_FORMAT(NOW(),\'%Y-%m-%d %h:%i:%s\'); -- 某一天所在月的天数: SELECT TIMESTAMPDIFF(DAY,\'2017-03-03\',(DATE_ADD(\'2017-03-03\',INTERVAL 1 MONTH))); set @dt = now(); select date_add(@dt, interval 1 day); - 加1天 select date_add(@dt, interval 1 hour); -加1小时 select date_add(@dt, interval 1 minute); - 加1分钟 select date_add(@dt, interval 1 second); -加1秒 select date_add(@dt, interval 1 microsecond);-加1毫秒 select date_add(@dt, interval 1 week);-加1周 select date_add(@dt, interval 1 month);-加1月 select date_add(@dt, interval 1 quarter);-加1季 select date_add(@dt, interval 1 year);-加1年 select TIMESTAMPDIFF(DAY,\'2019-06-01\',\'2019-06-05\'); select DATE_FORMAT(\'20190606\',\'%Y-%m-%d\'); -- 遍历指定时间段集合 select t.date from ( SELECT DATE_FORMAT(DATE_ADD(date_sub(\'2019-06-01\',INTERVAL 1 day), INTERVAL num DAY), \'%Y-%m-%d\') as date FROM ( SELECT @num:=@num+1 as num from (SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5) a, (SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5) b, (SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5) c, (SELECT 1 UNION SELECT 2 UNION SELECT 3 ) d, (SELECT @num:=0) m ) x)t where t.date<=\'2019-12-01\'; -- 遍历指定时间段集合2 select a.date,DAYOFWEEK(a.date)-1,WEEKDAY(a.date)+1,DAYNAME(DATE(a.date)) from ( select @num:=@num+1, date_format(adddate(date_sub(\'2020-01-02\',INTERVAL 1 day),INTERVAL @num day),\'%Y-%m-%d\') as date from t_student, (select @num:=0) t where ADDDATE(\'2020-01-02\',INTERVAL @num day)<= date_format(\'2020-03-01\',\'%Y-%m-%d\') ) a;