一、Oracle根据身份证判断性别:
女生身份证:
431382198103246985
男生身份证:
150921197208173492
SQL语句如下:
-
select decode(mod (to_number(substr(\'110228197802199547\' ,17, 1)),2 ),0, \'女\',\'男\' ) as sex from dual ;
-
select decode(mod (to_number(substr(\'530323197503252610\' ,17, 1)),2 ),0, \'女\',\'男\' ) as sex from dual ;
-
-
select decode(mod (to_number(substr(\'110228197802199547\' ,17, 1)),2 ),0, \'2\',\'1\' ) as sex from dual ;
-
select decode(mod (to_number(substr(\'530323197503252610\' ,17, 1)),2 ),0, \'2\',\'1\' ) as sex from dual ;
二、Oracle根据身份证判断年龄:
select (to_char(sysdate, \'yyyy\') - substr(\'430426199303014475\', 7, 4)) age from dual;
方法二
select trunc(to_number(to_char(sysdate,\'yyyymmdd\'))/10000 - to_number(to_char(to_date(\'1982-8-28\',\'yyyy-mm-dd\'),\'yyyymmdd\'))/10000) from dual
方法三
select trunc((to_char(sysdate,\'yyyyMMdd\')-to_char(to_date(substr(\'430426199303014475\',7,8),\'yyyy-MM-dd\'),\'yyyyMMdd\'))/10000) from dual;