sql比较两个字符串相同字符的个数

---分拆字符串
create  function [dbo].[f_splitstr_word](@SourceSql varchar(8000))
returns @temp table(No_Id int identity(1,1),F1 varchar(100))
as 
begin
declare @i int
set @SourceSql=rtrim(ltrim(@SourceSql))
set @i=LEN(@SourceSql)
while @i>=1
begin
  insert @temp values(substring(@SourceSql,1,1))
  set @SourceSql=substring(@SourceSql,2,LEN(@SourceSql)-1)
  set @i=LEN(@SourceSql)
end
if @SourceSql<>'' 
    insert @temp values(@SourceSql)
return 
end

--比较两个字符串相同字符的个数
create function [dbo].[funcomparestring]
(
       @stra nvarchar(200),
       @strb nvarchar(200)
)
returns int as
begin
    declare @strbase nvarchar(200)
    declare @rank int
    select @rank=0
       if len(@stra)>len(@strb)
          select @rank=count(*)
          from dbo.f_splitstr_word(@strb)
          where F1 in(select F1 from dbo.f_splitstr_word(@stra))
       else
          select @rank=count(*)
          from dbo.f_splitstr_word(@stra)
          where F1 in(select F1 from dbo.f_splitstr_word(@strb))
    return @rank
end