给定一组不含重复元素的整数数组 nums,返回该数组所有可能的子集(子集当中不包括重复的元素)

代码如下:

def subsets(nums):
    target=[[]]
    for num in nums:
        target+=[item + [num] for item in target]
    return target

nums=[1,2,3]
target=subsets(nums)
for item in target:
    print(item)

输出如下:

[]
[1]
[2]
[1, 2]
[3]
[1, 3]
[2, 3]
[1, 2, 3]

 

给定一组不含重复元素的整数数组 nums,返回该数组所有可能的子集(子集当中包括重复的元素)

代码如下:

def subsets(nums):
    target=[[]]
    nums.sort()
    for i in range(len(nums)):
        if i==0 or nums[i]!=nums[i-1]:
            l=len(target)
        for j in range(len(target)-l,len(target)):
            target.append(target[j] + [nums[i]])
    return target

nums=[1,2,2]
target=subsets(nums)
for item in target:
    print(item)

 

输出如下:

[]
[1]
[2]
[1, 2]
[2, 2]
[1, 2, 2]

 

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