jq

 

let  event = JQuery.event('keydown');

event.keyCode = 13;

$("input.pagination-num").trigger(e);//模拟页码框按下回车

 

js:

window.document.onkeydown = function(e){

  var isE = e || event;

  if(isE.keyCode == 46){

    return false;

  }

}

相关文章:

  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-02-01
  • 2022-12-23
  • 2022-12-23
  • 2021-11-22
猜你喜欢
  • 2021-10-09
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
相关资源
相似解决方案