16进制编码与字符串的互相转化

Q:16进制编码与字符串的互相转化

A: 

string  ddd  =   " jinjazz路过 " ;

             string  strHex  =  BitConverter.ToString(System.Text.Encoding.Default.GetBytes(ddd));

            Console.WriteLine(strHex);

             string [] strChars = strHex.Split( ' - ' );
             byte [] b  =   new   byte [strChars.Length];
             for  ( int  i = 0 ;i < strChars.Length;i ++ )
             ...                 b[i]  =  Convert.ToByte(strChars[i],  16 );
            }
             string  ddd1  =  System.Text.Encoding.Default.GetString(b);
            Console.WriteLine(ddd1);
             return ;
            
             /**/ /*
            6A-69-6E-6A-61-7A-7A-C2-B7-B9-FD
            jinjazz路过
             */