//定义动态对象转换JSON字符串
dynamic car = new
{
   Name = "Audi A8L",
   Model= " www.cscode.net:C/S框架网"
};
   
   string jsonData= JsonConvert.SerializeObject(car);

   //JSON: {"Name":"Audi A8L","Model":" www.cscode.net:C/S框架网"}
   
 car model= Newtonsoft.Json.JsonConvert.DeserializeObject<car>(jsonData); //

 

转载:http://www.csframework.com/archive/1/arc-1-20170918-2337.htm

相关文章:

  • 2021-12-02
  • 2021-06-01
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-04-12
猜你喜欢
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-01-07
  • 2021-12-25
  • 2022-12-23
  • 2021-11-28
相关资源
相似解决方案