Map<String, List<Model>> map = new HashMap<>();
// 如何获取相同的num 的对象做运算
(Model model6 : list) {
String s = model6.getNum();
if (map.containsKey(s)) {
map.get(s).add(model6);
} else {
ArrayList<Model> NumList = new ArrayList<Model>();
NumList.add(model6);
map.put(s, NumList);
}
}
Java8写法
Map<String, List<Model>> result = list.stream().collect(Collectors.groupingBy(e -> e.getB()));