如：
'ab-cd-ef-gh'
现在要取到，第三个'-'后面的gh
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declare @s varchar(100);set @s = 'ab-cd-ef-gh';select right(@s, charindex('-',reverse(@s))-1) |
declare @str char(20)
set @str='ab-cd-ef-gh'
select stuff(@str,1,len(@str)-charindex('-',reverse(rtrim(@str)))+1,'') as result
select substring(@str,len(@str)-charindex('-',reverse(rtrim(@str)))+2,charindex('-',reverse(rtrim(@str)))-1) as result
select reverse(left(reverse(@str),charindex('-',reverse(@str))-1)) as result
select right(@str,charindex('-',reverse(@str))-1) as result