以下函数允许计算两个数的乘积,请稍加改造,变成可接收一个或多个数并计算乘积
def product(x, y):
return x * y

# -*- coding: utf-8 -*-

def prodouct(*num):
    n = 1
    for x in num:
        n = n * x
    return n

# 测试
print('print(5)=',prodouct(5))
print('print(5,6)=',prodouct(5,6))
print('print(5,6,7)=',prodouct(5,6,7))
print('print(5,6,7,9)=',prodouct(5,6,7,9))

if prodouct(5) != 5:
    print('测试失败')
elif prodouct(5,6) != 30:
    print('测试失败')
elif prodouct(5,6,7) != 210:
    print('测试失败')
elif prodouct(5,6,7,9) != 1890:
    print('测试失败')

 

方法二:

# -*- coding: utf-8 -*-

def prodouct(x,*num):
    if len(num) > 0 :
        for y in num:
            x = x * y
    return x

# 测试
print('print(5)=',prodouct(5))
print('print(5,6)=',prodouct(5,6))
print('print(5,6,7)=',prodouct(5,6,7))
print('print(5,6,7,9)=',prodouct(5,6,7,9))

if prodouct(5) != 5:
    print('测试失败')
elif prodouct(5,6) != 30:
    print('测试失败')
elif prodouct(5,6,7) != 210:
    print('测试失败')
elif prodouct(5,6,7,9) != 1890:
    print('测试失败')

  

  

相关文章:

  • 2022-12-23
  • 2022-01-10
  • 2021-11-07
  • 2022-12-23
  • 2022-12-23
  • 2021-07-12
  • 2021-07-29
  • 2022-12-23
猜你喜欢
  • 2022-12-23
  • 2021-10-14
  • 2021-12-19
  • 2022-12-23
  • 2022-01-16
  • 2022-12-23
  • 2021-09-03
相关资源
相似解决方案