编写一个 SQL 查询,获取 Employee 表中第 高的薪水(Salary)。

+----+--------+
| Id | Salary |
+----+--------+
| 1  | 100    |
| 2  | 200    |
| 3  | 300    |
+----+--------+

例如上述 Employee 表,n = 2 时,应返回第二高的薪水 200。如果不存在第 高的薪水,那么查询应返回 null

+------------------------+
| getNthHighestSalary(2) |
+------------------------+
| 200                    |
+------------------------+
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
declare m int;
SET m = N - 1;
  RETURN (
      # Write your MySQL query statement below.
          SELECT
            (
                SELECT DISTINCT
                    Salary
                FROM
                    employee
                ORDER BY
                    Salary DESC
                LIMIT m,1
            ) AS getNthHighestSalary
    
  );
END

sql 中 limit 与 limit,offset连用

SELECT * FROM employee ORDER BY Salary ASC LIMIT 3,2;

从当前的第个之后的第四位开始往后数

sql 中 limit 与 limit,offset连用


SELECT * FROM employee ORDER BY Salary ASC LIMIT 2 OFFSET 3;

从当前数据中选取2个,从第三位往后数,就是第四位开始

 

 

 

 

相关文章: