不必一个字符一个字符的匹配。

 

 

+ (void)openUrl:(NSString*)link

{

if(0 == [link length])

return;

 

NSRange range = [link rangeOfString:@"target=_blank"];

if(range.location != NSNotFound)

{

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:link]];

}

}

 
 
 

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