问题描述:在使用request.GetResponse时,如果是400错误,将抛出异常信息,而获取不到返回内容,所以返回的内容只能在catch上面获取,转载于

http://blog.csdn.net/ahywg/article/details/26267113

解决方法:

 

 WebRequest request = WebRequest.Create("网址");
 Stream stream=null;
  try
  {
   using (WebResponse response = request.GetResponse())
   {
    	stream=response.GetResponseStream();
   }
  }  
  catch (WebException e)
  {   
	stream=e.Response.GetResponseStream();
}

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