select '全部' AS `organ_category`, COUNT(*) AS amount  
FROM `organ_new` 
WHERE `city_code` ='SZ0755' AND `organ_type` ='P' AND `state` ='1' 
union all
select
		`organ_category` ,COUNT(1) AS `amount`
		FROM `organ_new`
		WHERE `city_code` = 'SZ0755' AND `organ_type` ='P' AND
		`state` ='1'
		GROUP BY CONVERT(`organ_category` USING gbk) COLLATE
		gbk_chinese_ci,`organ_category`
		ASC

  mysql分组统计以及全部统计union all使用

select '全部' AS `area`, COUNT(*) AS amount  
FROM `organ_new` 
WHERE `city_code` ='SZ0755' AND `organ_type` ='P' AND `state` ='1' 
union all
select `area` ,COUNT(1)  AS `amount` 
		FROM `organ_new` 
		WHERE `city_code` ='SZ0755' AND `organ_type` ='P' AND `state` ='1' 
		GROUP BY   CONVERT(`area`  USING gbk) COLLATE
		gbk_chinese_ci,`area` ASC

  mysql分组统计以及全部统计union all使用

 

相关文章:

  • 2022-12-23
  • 2021-07-28
  • 2022-02-09
  • 2021-04-24
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-06-22
猜你喜欢
  • 2021-12-28
  • 2022-12-23
  • 2021-08-18
  • 2022-12-23
  • 2021-10-21
  • 2022-12-23
  • 2022-12-23
相关资源
相似解决方案