整数保留最高位

        number = ((number & 0xFFFF0000) != 0) ? (number & 0xFFFF0000) : (number & 0x0000FFFF);
        number = ((number & 0xFF00FF00) != 0) ? (number & 0xFF00FF00) : (number & 0x00FF00FF);
        number = ((number & 0xF0F0F0F0) != 0) ? (number & 0xF0F0F0F0) : (number & 0x0F0F0F0F);
        number = ((number & 0xCCCCCCCC) != 0) ? (number & 0xCCCCCCCC) : (number & 0x33333333);
        number = ((number & 0xAAAAAAAA) != 0) ? (number & 0xAAAAAAAA) : (number & 0x55555555);

 

相关文章:

  • 2022-12-23
  • 2020-07-17
  • 2021-12-21
  • 2021-11-14
  • 2022-12-23
  • 2021-08-06
  • 2021-08-03
  • 2021-11-14
猜你喜欢
  • 2021-06-19
  • 2021-08-31
  • 2021-12-15
  • 2021-11-28
相关资源
相似解决方案