//值传递与引用传递的差别

#include <iostream>
#include <iomanip>
using namespace std;

void fiddle(int in1, int &in2)
{
	in1 = in1 + 100;
	in2 = in2 + 100;
	cout << "The values are ";
	cout << setw(5) << in1;
	cout << setw(5) << in2 << endl;
}

int main()
{
	int v1 = 7, v2 = 12;
	cout << "The values are:";
	cout << setw(5) << v1;
	cout << setw(5) << v2 << endl;
	fiddle(v1, v2);
	cout << "The values are:";
	cout << setw(5) << v1;
	cout << setw(5) << v2 << endl;
	system("pause");
	return 0;
}


执行结果:

7 12

107 112

7 112 


能够得出结论,假设穿引用将会改变变量最初的值,而假设传值在函数中使用后并不会改变其原来的值

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