>>> a = ["aa","bb","aa","cc","aa","dd","bb","aa","cc"]
>>> a
['aa', 'bb', 'aa', 'cc', 'aa', 'dd', 'bb', 'aa', 'cc']
>>> b = a.count("aa")
>>> b
4
>>> c = -1
>>> for i in range(b):
    c = a.index("aa",c + 1,len(a))
    print("aa",c)

    
aa 0
aa 2
aa 4
aa 7

 

相关文章:

  • 2022-12-23
  • 2022-12-23
  • 2021-07-21
  • 2022-01-02
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
猜你喜欢
  • 2022-12-23
  • 2022-12-23
  • 2021-09-13
  • 2022-12-23
  • 2022-12-23
  • 2021-12-19
  • 2021-12-16
相关资源
相似解决方案