Revit二次开发之“过滤得到某一标高上的所有风管”

风管的Level值为空，墙对应Level,风管对应ReferenceLevel

//找到标高1上的所有风管
[Transaction(TransactionMode.Manual)]
[Regeneration(RegenerationOption.Manual)]
//[Journaling(JournalingMode.NoCommandData)]
public class cmdGetLevelDuct : IExternalCommand
{
    public Result Execute(ExternalCommandData cmdData, ref string message, ElementSet elements)
    {
        UIDocument uiDoc = cmdData.Application.ActiveUIDocument;//base.m_uiDoc
        Selection selection = uiDoc.Selection;

        Transaction ts = new Transaction(uiDoc.Document, "LevelDuct");
        ts.Start();

        FilteredElementCollector collector = new FilteredElementCollector(uiDoc.Document);
        collector.OfClass(typeof(Duct)).OfCategory(BuiltInCategory.OST_DuctCurves);

        foreach (Element el in collector)
        {
            Duct duct = el as Duct;
            if (duct.ReferenceLevel.Name == "标高 1")
                TaskDialog.Show("title", duct.Id.ToString());
        }

        ts.Commit();

        return Result.Succeeded;
    }
}

from:http://revit.5d6d.com/thread-1204-1-1.html