<SCRIPT type=text/javascript>
//创建弹出窗口( popup )对象
var oPopup = window.createPopup();

function contextMenu(){ 
    with (oPopup.document.body) {
          style.border="solid red 1px"; 
          innerHTML="你好!!!";
    }
    var left = event.x;
    var top = event.y;
    oPopup.show(left , top , 180, 60, document.body);
}
</script>
<body oncontextmenu="contextMenu(); return false;">
<br>
点击弹出窗口外面的区域关闭它<br><br>
<input type=button value=" 关闭弹出窗口 " onclick="oPopup.hide();">

</body>

相关文章:

  • 2022-01-15
  • 2021-04-25
  • 2021-06-21
  • 2022-12-23
  • 2022-01-11
  • 2021-10-19
  • 2021-06-24
猜你喜欢
  • 2022-12-23
  • 2021-12-10
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-09-17
  • 2022-12-23
相关资源
相似解决方案