温故一下上一节所学习的生产者消费者代码:
两个线程时:
通过标志位flag的if判断和同步函数互斥较好解决两个线程,一个生产者、一个消费者交替执行的功能
类名:ProducterConsumerDemo.java
代码:
1 class ProducterConsumerDemo 2 { 3 public static void main(String[] args) 4 { 5 Resources r =new Resources(); 6 Productor pro =new Productor(r); 7 Consumer con = new Consumer(r); 8 9 Thread t1 =new Thread(pro); 10 Thread t2 =new Thread(con); 11 t1.start(); 12 t2.start(); 13 System.out.println("Hello World!"); 14 } 15 } 16 17 class Resources 18 { 19 private String name; 20 private int count =1; 21 private boolean flag =false; 22 23 public synchronized void set(String name) 24 { 25 if(flag) 26 try{this.wait();}catch(Exception e){} 27 this.name = name+"--"+count++; 28 29 System.out.println(Thread.currentThread().getName()+"生产者"+this.name); 30 flag =true; 31 //唤醒对方进程 32 this.notify(); 33 34 } 35 public synchronized void out() 36 { 37 if(!flag) 38 try{this.wait();}catch(Exception e){} 39 40 System.out.println(Thread.currentThread().getName()+" ....消费者...."+this.name); 41 flag =false; 42 //唤醒对方进程 43 this.notify(); 44 45 } 46 } 47 48 class Productor implements Runnable 49 { 50 private Resources res; 51 Productor(Resources res){ 52 this.res =res; 53 } 54 public void run(){ 55 while(true){ 56 res.set("++商品++"); 57 } 58 } 59 60 } 61 62 class Consumer implements Runnable 63 { 64 private Resources res; 65 Consumer(Resources res){ 66 this.res =res; 67 } 68 public void run(){ 69 while(true){ 70 res.out(); 71 } 72 } 73 74 }