local aa = {{a=11},{a=44},{a=33},{a=2} }
table.sort(aa,function(a,b)
  return a.a>b.a
end)

for k, v in pairs(aa[1]) do
  ngx.say(k)
  ngx.say(v)
end
for k, v in pairs(aa[2]) do
  ngx.say(k)
  ngx.say(v)
end
for k, v in pairs(aa[3]) do
  ngx.say(k)
  ngx.say(v)
end
for k, v in pairs(aa[4]) do
  ngx.say(k)
  ngx.say(v)
end

结果:

a
44
a
33
a
11
a
2

相关文章:

  • 2022-12-23
  • 2022-12-23
  • 2021-08-09
  • 2021-12-18
  • 2021-11-29
  • 2022-12-23
  • 2022-12-23
  • 2021-11-17
猜你喜欢
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-11-09
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
相关资源
相似解决方案