查找:({^:b@})\n(^:b+\[.+\]\n)@^:b+public 替换:\1/// <summary>\n\1///\n\1/// </summary>\0 相关文章: 2022-01-30 2021-11-20 2022-12-23 2021-10-24 2021-08-26 2021-06-23 2022-12-23 2021-10-22