斐波纳奇数列:

  定义为F0=0,F1=1,......Fn=F(n-1)+F(n-2)

  1,1,2,3,5,8,13,21,34,55.......

void FibonacciOdd(int n)
{ 
    int prev_1 = 0, prev_2 = 0, item = 0;
    for(int i=0;i<=n;i++)
    { 
        if(i==0)
            item = 0;
        else if(i==1)
        {
            item = pre1 = 1;
        }
        else
        {
            item = prev_1 + prev_2;
            pre_2 = pre_1;
            pre_1 = item;
        }
        //cout<<"第"<<i<<"项"<<item<<endl;
    }
}

 

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