--序号递归
WITH RoulettePrizeItem
AS ( SELECT RowNum ,
EventId
FROM #tbRoulettePrizeItem
WHERE RowNum = 1
UNION ALL
SELECT d.RowNum ,
d.EventId
FROM RoulettePrizeItem tbrpi
INNER JOIN #tbRoulettePrizeItem d ON d.RowNum = tbrpi.RowNum + 1
--关联递归
假如我们要查询ID为003的数据的所有子节点我们可以使用CTE 递归查询完成...
[sql] view plaincopyprint?
if OBJECT_ID(\'tb\',\'N\') is not null
drop table tb;
create table tb(id varchar(3) , pid varchar(3) , name varchar(10));
insert into tb values(\'001\' , null , \'广东省\');
insert into tb values(\'002\' , \'001\' , \'广州市\');
insert into tb values(\'003\' , \'001\' , \'深圳市\') ;
insert into tb values(\'004\' , \'002\' , \'天河区\') ;
insert into tb values(\'005\' , \'003\' , \'罗湖区\');
insert into tb values(\'006\' , \'003\' , \'福田区\') ;
insert into tb values(\'007\' , \'003\' , \'宝安区\') ;
insert into tb values(\'008\' , \'007\' , \'西乡镇\') ;
insert into tb values(\'009\' , \'007\' , \'龙华镇\');
insert into tb values(\'010\' , \'007\' , \'松岗镇\');
select * from tb;
with cte as
(
select a.id,a.name,a.pid from tb a where id=\'003\'
union all
select k.id,k.name,k.pid from tb k inner join cte c on c.id = k.pid
)select * from cte
查询结果如下：
003 深圳市 001
005 罗湖区 003
006 福田区 003
007 宝安区 003
008 西乡镇 007
009 龙华镇 007
010 松岗镇 007
来源： <http://blog.csdn.net/myxx520/article/details/6922682>