codeforces 1136A：
题意：一本书有n个章节，每个章节的分别在li到ri页，小明读完书后将书折在第k页，问还有多少章节没有读
题解：控制k在li~ri的范围内后输出n-i即可
#include <set> #include <map> #include <deque> #include <queue> #include <stack> #include <cmath> #include <ctime> #include <bitset> #include <cstdio> #include <string> #include <vector> #include <cstdlib> #include <cstring> #include <iostream> #include <algorithm> using namespace std; typedef long long LL; typedef pair<LL, LL> pLL; typedef pair<LL, int> pLi; typedef pair<int, LL> pil;; typedef pair<int, int> pii; typedef unsigned long long uLL; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define bug printf("*********\n") #define FIN freopen("input.txt","r",stdin); #define FON freopen("output.txt","w+",stdout); #define IO ios::sync_with_stdio(false),cin.tie(0) #define debug1(x) cout<<"["<<#x<<" "<<(x)<<"]\n" #define debug2(x,y) cout<<"["<<#x<<" "<<(x)<<" "<<#y<<" "<<(y)<<"]\n" #define debug3(x,y,z) cout<<"["<<#x<<" "<<(x)<<" "<<#y<<" "<<(y)<<" "<<#z<<" "<<z<<"]\n" LL read() { int x = 0, f = 1; char ch = getchar(); while(ch < '0' || ch > '9') { if(ch == '-')f = -1; ch = getchar(); } while(ch >= '0' && ch <= '9') { x = x * 10 + ch - '0'; ch = getchar(); } return x * f; } const double eps = 1e-8; const int mod = 1e9 + 7; const int maxn = 2e5 + 5; const int INF = 0x3f3f3f3f; const LL INFLL = 0x3f3f3f3f3f3f3f3f; int l[maxn]; int r[maxn]; int main() { #ifndef ONLINE_JUDGE FIN #endif int n, k; scanf("%d", &n); for(int i = 0; i < n; i++) { scanf("%d%d", &l[i], &r[i]); } scanf("%d", &k); for(int i = 0; i < n; i++) { if(l[i] <= k && k <= r[i]) { cout << n - i << endl; return 0; } } return 0; }