Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 132768/132768 K (Java/Others)
Total Submission(s): 304 Accepted Submission(s): 170
Special Judge
Problem Description
Chiaki has n points.
Input
There are multiple test cases. The first line of input contains an integer 10000.
Output
For each test case, output i-th triangle use. If there are multiple solutions, you can output any of them.
Sample Input
1
1
1 2
2 3
3 5
Sample Output
1 2 3
题意:给你3*n个点,求你构造出的n个三角形的id位置(之前输入的位置)是哪些 ,三角形不能重合
题解:按照x轴排序,然后依次输出就行,注意只能用scanf输入,不然会T
#include <bits/stdc++.h> using namespace std; const int maxn = 1e4+5; struct node{ int x,y,id; bool operator < (const node & a)const{ return x<a.x; } }p[maxn]; int main(int argc, char const *argv[]) { int T; scanf("%d",&T); while(T--){ int n; scanf("%d",&n); for(int i=1;i<=n*3;i++){ scanf("%d %d",&p[i].x,&p[i].y); p[i].id=i; } sort(p+1,p+n*3+1); for(int i=1;i<=n*3;i+=3){ printf("%d %d %d\n",p[i].id,p[i+1].id,p[i+2].id); } } return 0; }