问题描述:

 

Given two binary trees, write a function to check if they are the same or not.

 

Two binary trees are considered the same if they are structurally identical and the nodes have the same value.

 

Example 1:

 

Input:     1         1
          / \       / \
         2   3     2   3

        [1,2,3],   [1,2,3]

Output: true

 

Example 2:

 

Input:     1         1
          /           \
         2             2

        [1,2],     [1,null,2]

Output: false

 

Example 3:

 

Input:     1         1
          / \       / \
         2   1     1   2

        [1,2,1],   [1,1,2]

Output: false

 

思路:

考虑递归解法,将大问题化解为无数个类似的小问题

 

 

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution:
    def isSameTree(self, p: TreeNode, q: TreeNode) -> bool:
        if p == None and q ==None:
            return True
        elif p == None or q ==None or p.val != q.val:
            return False
        if p.val == q.val :
            return self.isSameTree(p.left,q.left)  and self.isSameTree(p.right,q.right) 

 

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