LeetCode Jump Game

Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Determine if you are able to reach the last index.

For example:
A = [2,3,1,1,4], return true.

A = [3,2,1,0,4], return false.

题意：每一个坐标的数值是能跳的步数，问能否到最后一个。

思路：更新最远的能到的距离就是了。

class Solution {
public:
    bool canJump(int A[], int n) {
        if (n == 0 || n == 1) return true;

        int Max = A[0];
        for (int i = 1; i < n && i <= Max; i++) {
            Max = (A[i] + i) > Max ? (A[i] + i) : Max;
        }

        return Max >= n-1;
    }
};