var a = [1,2,4];var b = [3,4,5];undefineda[1, 2, 4]b[3, 4, 5]var c = a.concat(b)undefinedc[1, 2, 4, 3, 4, 5] 相关文章: 2021-12-24 2022-12-23 2022-12-23 2022-12-23 2022-12-23 2022-12-23 2022-12-23 2021-11-05