利用函数计算字符串1中出现字符串2的次数

 

 

 

 

'a'was found in "This is a test".
'z'was not found in "This is a test".

利用函数计算字符串1中出现字符串2的次数

 

#include <iostream>
using std::cout;
using std::endl;
int main()
{
char *string1="asdfasdfasdf";
const char *string2="df";
int i=0;
while (strstr(string1,string2)!=NULL)
    {
++i;
        string1=strstr(string1,string2);
        string1+=strlen(string2);

    }

    cout<<i<<endl;
return 0;
}