判断当前数值，是否为2的n次方

/// <summary>
        /// 主要思路
        /// 应用了位运算
        /// </summary>
        public static void FinB()
        {
            int n = Convert.ToInt32(Console.ReadLine());
            if(n==0)
            {
                Console.WriteLine("N");
                Console.ReadKey();
                return;
            }
            if (n != 1)
            {
                //n和n-1进行与运算，当n为4(二进制100),4-1为3(二进制11)值等于0，值为0时说明当前数值为2的N次方
                Console.WriteLine((n & (n - 1)) == 0 ? (Convert.ToString(n, 2).Length - 1 + "Y") : "N");
            }
            else
            {
                Console.WriteLine("Y");
            }

            Console.ReadKey();
        }