import java.util.regex.Pattern;

public class ZhengZe {

 /**
  * @param args
  */
 public static void main(String[] args) {
  Pattern p = Pattern
    .compile("^((\\d{2}(([02468][048])|([13579][26]))[\\/\\/\\s]?((((0?" +
      "[13578])|(1[02]))[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))" +
      "|(((0?[469])|(11))[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|" +
      "(0?2[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])))))|(\\d{2}(([02468][12" +
      "35679])|([13579][01345789]))[\\/\\/\\s]?((((0?[13578])|(1[02]))" +
      "[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))" +
      "[\\/\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\\/\\/\\s]?((0?[" +
      "1-9])|(1[0-9])|(2[0-8]))))))");
      //(\\s(((0?[0-9])|([1-2][0-3]))\\:([0-5]?[0-9])((\\s)|(\\:([0-5]?[0-9])))))?$ 时间部分00:00:00
  String s = "2003/02/29";
  System.out.println(s + " " + p.matcher(s).matches());

  s = "2004/02/29";
  System.out.println(s + " " + p.matcher(s).matches());

  s = "2004/04/31";
  System.out.println(s + " " + p.matcher(s).matches());

  s = "2004/04/30";
  System.out.println(s + " " + p.matcher(s).matches());

  s = "2004/04/30";
  System.out.println(s + " " + p.matcher(s).matches());

  s = "2004/09/30";
  System.out.println(s + " " + p.matcher(s).matches());
 }

}

相关文章:

  • 2022-01-14
  • 2022-12-23
  • 2022-01-10
  • 2021-12-11
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
猜你喜欢
  • 2021-12-17
  • 2021-11-14
  • 2022-12-23
  • 2021-10-09
  • 2021-05-30
  • 2022-12-23
  • 2021-12-27
相关资源
相似解决方案