Select count(distinct c_ajbh) from t_aj 改写后: Select count(*) from (select distinct c_ajbh from t_aj where ...)t2 相关文章: 2022-12-23 2021-08-29 2021-11-29 2021-11-03 2022-01-11 2022-12-23 2021-07-07 2022-12-23