Select count(distinct c_ajbh) from t_aj
改写后:
Select count(*) from (select distinct c_ajbh from t_aj where ...)t2

相关文章:

  • 2022-12-23
  • 2021-08-29
  • 2021-11-29
  • 2021-11-03
  • 2022-01-11
  • 2022-12-23
  • 2021-07-07
  • 2022-12-23
猜你喜欢
  • 2021-06-02
  • 2021-06-16
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-11-29
相关资源
相似解决方案