按照 , 或者特定的字符进行分割，把值取出来，举个例子，数据是：
a,b,c
d,e,f
显示结果是：
a
b
c
d
e
f
解决方法：
拆分表:
if not object_id('Tab') is null
drop table Tab
Go Create table Tab([Col1] int,[COl2] nvarchar(5))
Insert Tab
select 1,N'a,b,c' union all
select 2,N'd,e' union all
select 3,N'f'
Go --SQL2000用辅助表: if object_id('Tempdb..#Num') is not null
drop table #Num
go select top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns b
Select a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID)
from Tab a,#Num b
where charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','
--2000不使用辅助表 Select a.Col1,COl2=substring(a.Col2,b.number,charindex(',',a.Col2+',',b.number)-b.number)
from Tab a join master..spt_values b
ON B.type='p' AND B.number BETWEEN 1 AND LEN(A.col2)
where substring(','+a.COl2,b.number,1)=','
SQL2005用Xml: select a.COl1,b.Col2
from (select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)a
outer apply
(select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))b
SQL05用CTE: ;with roy as (select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tab
union all
select Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>''
) select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)
生成结果: /* Col1 COl2 ----------- ----- 1 a 1 b 1 c 2 d 2 e 3 f */方法：
if not object_id(N'Tempdb..#T') is null
drop table #T
Go Create table #T([Col1] nvarchar(9))
Insert #T
select N'苹果/橘子/梨' union all
select N'香蕉/鸭蛋/巧克力' union all
select N'饼干/果粒橙'
Go Select substring(a.[Col1],b.number,charindex('/',a.[Col1]+'/',b.number)-b.number)
from #T AS a,master.dbo.spt_values AS b
WHERE b.type='P' AND CHARINDEX('/','/'+[Col1],b.number)=b.number