A. Pasha and Pixels

题目大意:给出n*m的棋盘,初始为全白,每次在上面使一个格子变黑,问多少次的时候使得棋盘上出现2×2的黑格

思路:模拟

 1 #include<iostream>
 2 #include<cstring>
 3 #include<cstdio>
 4 #include<queue>
 5 #define maxn 900000
 6 #define LL long long
 7 using namespace std;
 8 bool map[1001][1001];
 9 int main()
10 {
11         int n,m,k,ans=0,x,y;
12         scanf("%d%d%d",&n,&m,&k);
13         for(int i=1;i<=k;i++)
14         {
15                 scanf("%d%d",&x,&y);
16                 map[x][y]=1;
17                 if(map[x-1][y]&&map[x-1][y-1]&&map[x][y-1]){ans=i;break;}
18                 if(map[x+1][y]&&map[x+1][y+1]&&map[x][y+1]){ans=i;break;}
19                 if(map[x-1][y]&&map[x-1][y+1]&&map[x][y+1]){ans=i;break;}
20                 if(map[x+1][y]&&map[x+1][y-1]&&map[x][y-1]){ans=i;break;}
21         }
22         printf("%d",ans);
23         return 0;
24 }
View Code

相关文章: