C# ASP.NET Core使用HttpClient的同步和异步请求

引用 Newtonsoft.Json

        // Post请求
        public string PostResponse(string url,string postData,out string statusCode)
        {
            string result = string.Empty;
            //设置Http的正文
            HttpContent httpContent = new StringContent(postData);
            //设置Http的内容标头
            httpContent.Headers.ContentType = new System.Net.Http.Headers.MediaTypeHeaderValue("application/json");
            //设置Http的内容标头的字符
            httpContent.Headers.ContentType.CharSet = "utf-8";
            using(HttpClient httpClient=new HttpClient())
            {
                //异步Post
                HttpResponseMessage response = httpClient.PostAsync(url, httpContent).Result;
                //输出Http响应状态码
                statusCode = response.StatusCode.ToString();
                //确保Http响应成功
                if (response.IsSuccessStatusCode)
                {
                    //异步读取json
                    result = response.Content.ReadAsStringAsync().Result;
                }
            }
            return result;
        }


        // 泛型：Post请求
        public T PostResponse<T>(string url,string postData) where T:class,new()
        {
            T result = default(T);
 
            HttpContent httpContent = new StringContent(postData);
            httpContent.Headers.ContentType = new System.Net.Http.Headers.MediaTypeHeaderValue("application/json");
            httpContent.Headers.ContentType.CharSet = "utf-8";
            using(HttpClient httpClient=new HttpClient())
            {
                HttpResponseMessage response = httpClient.PostAsync(url, httpContent).Result;
 
                if (response.IsSuccessStatusCode)
                {
                    Task<string> t = response.Content.ReadAsStringAsync();
                    string s = t.Result;
                    //Newtonsoft.Json
                    string json = JsonConvert.DeserializeObject(s).ToString();
                    result = JsonConvert.DeserializeObject<T>(json); 
                }
            }
            return result;
        }

post