1. Function: 16进制转字符串
Create FUNCTION [dbo].[f_hextostr] (@hexstring VARCHAR(max)) RETURNS VARCHAR(max) AS begin declare @char1 char(1), @char2 char(1), @strlen int, @currpos int, @result varchar(max) set @strlen=len(@hexstring) set @currpos=1 set @result='' while @currpos<@strlen begin set @char1=substring(@hexstring,@currpos,1) set @char2=substring(@hexstring,@currpos+1,1) if (@char1 between '0' and '9' or @char1 between 'A' and 'F') and (@char2 between '0' and '9' or @char2 between 'A' and 'F') set @result=@result+ char((ascii(@char1)-case when @char1 between '0' and '9' then 48 else 55 end)*16+ ascii(@char2)-case when @char2 between '0' and '9' then 48 else 55 end) set @currpos = @currpos+2 end return @result end