public List<String> letterCombinations(String digits) {
    LinkedList<String> ans = new LinkedList<String>();
    if(digits == null || digits.length() == 0) return ans;
    String[] mapping = new String[] {"0", "1", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"};
    ans.add("");
    for(int i =0; i<digits.length();i++){
        int x = Character.getNumericValue(digits.charAt(i));
        while(ans.peek().length()==i){
            String t = ans.remove();
            for(char s : mapping[x].toCharArray())
                ans.add(t+s);
        }
    }
    return ans;
    }

相关文章:

  • 2021-10-26
  • 2021-12-19
  • 2022-12-23
  • 2021-11-21
  • 2022-02-15
  • 2022-12-23
  • 2021-11-16
猜你喜欢
  • 2021-08-09
  • 2022-12-23
  • 2021-11-23
  • 2021-11-24
  • 2021-11-30
相关资源
相似解决方案