把”0102030405”分成5组('0', '1'), ('0', '2'), ('0', '3'), ('0', '4'), ('0', '5')
re.findall(r"(\d)(\d)",s)
>>> re.findall(r"(\d)(\d)",s)
[('0', '1'), ('0', '2'), ('0', '3'), ('0', '4'), ('0', '5')]
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把”0102030405”分成5组('0', '1'), ('0', '2'), ('0', '3'), ('0', '4'), ('0', '5')
re.findall(r"(\d)(\d)",s)
>>> re.findall(r"(\d)(\d)",s)
[('0', '1'), ('0', '2'), ('0', '3'), ('0', '4'), ('0', '5')]
相关文章：