1、两个统计量的减法：
select
(select count(*) from defect)-(select count(*) from defect where cljg like '%合格%' and cljg not like '%不合格%') as count
from dual
相关文章：
相似解决方案
热门标签
1、两个统计量的减法：
select
(select count(*) from defect)-(select count(*) from defect where cljg like '%合格%' and cljg not like '%不合格%') as count
from dual
相关文章：