方法1：select a.* from data_subtaskregionschedule a inner join(select subregionid,max(updatetime) maxupdatetime
from data_subtaskregionschedule group by subregionid) b on a.subregionid=b.subregionid and a.updatetime
=b.maxupdatetime;
方法2：select * from data_subtaskregionschedule,(select
subregionid,max(updatetime) maxdate from
data_subtaskregionschedule group
by subregionid) t where
data_subtaskregionschedule.subregionid=t.subregionid and
data_subtaskregionschedule.updatetime=t.maxdate;
实测可行