Time Limit:500MS
Memory Limit:32768KB
Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
以下是代码：
#include <cstdio>
using namespace std;
int main(){
int n,sum;
while(scanf("%d",&n)!=EOF){
sum=0;
for(int i=1;i<=n;i++)sum+=i;
printf("%d\n\n",sum);
}
}