sqlserver 时间字符串转化为时间格式

select convert(datetime,substring(left('20170719172552',8)+' ' + substring('20170719172552',9,2)+':' + substring('20170719172552',11,2)+':' + substring('20170719172552',13,2),1,20))

select substring('D:\\files,3,len('D:\\files)-2)
 --去掉前两位路径D: