2017 Multi-University Training Contest - Team 1 1011&&HDU 6043 KazaQ's Socks【规律题，数学，水】

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 338    Accepted Submission(s): 212

 

Sample Input

3 7
3 6
4 9

Sample Output

Case #1: 3
Case #2: 1
Case #3: 2

Source

2017 Multi-University Training Contest - Team 1

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=6043

分析：

 

然后分别去判断即可！详细请看代码。

下面给出AC代码：

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 typedef long long ll;
 4 int main()
 5 {
 6     ll n,m;
 7     ll p=1;
 8     while(scanf("%lld%lld",&n,&m)!=EOF)
 9     {
10         printf("Case #%lld: ",p++);
11         if(m<=n)
12         {
13             printf("%lld\n",m);
14             continue;
15         }
16         ll c=m-n;
17         if(c%(2*(n-1))==0)
18         {
19             printf("%lld\n",n);
20             continue;
21         }
22         if(c%(2*(n-1))<=n-1)
23             printf("%lld\n",c%(2*(n-1)));
24         else
25         {
26             ll k=c%(2*(n-1))%(n-1);
27             printf("%lld\n",k);
28         }
29     }
30     return 0;
31 }